Home
Class 12
CHEMISTRY
Rate constant of a first order reaction ...

Rate constant of a first order reaction is `0.45 sec^(-1)`, calculate its half life.

Text Solution

Verified by Experts

Given data : Rate constant of a first order reaction `(k)=0.45 sec^(-1)`
Formula : `t_(1//2)=(0.693)/(k)`
Solution : `t_(1//2)=(0.693)/(k)=(0.693)/(0.45)`
Half - life period = 1.54 sec.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    SURA PUBLICATION|Exercise UNIT TEST (CHOOSE THE CORRECT ANSWER)|5 Videos

  • CHEMICAL KINETICS

    SURA PUBLICATION|Exercise UNIT TEST (SHORT ANSWER)|2 Videos

  • CHEMICAL KINETICS

    SURA PUBLICATION|Exercise HOTS|2 Videos

  • CARBONYL COMPOUND

    SURA PUBLICATION|Exercise UNIT TEST (LONG ANSWER)|1 Videos

  • CHEMISTRY IN EVERYDAY LIFE

    SURA PUBLICATION|Exercise UNIT TEST (LONG ANSWER )|1 Videos

Similar Questions

Explore conceptually related problems

The rate constant for a first order reaction is 1.54xx10^(-3)s^(-1) . Calculate its half life time.

(i) The rate constant for a first order reaction is 1.54 times 10^(-3)s^(-1) . Calculate its half life time. (ii) Explain about protective action of colloid.

The equilibrium constant Kc for A_((g))hArrB_((g)) is 2.5xx10^(-2) . The rate constant of the forward reaction is 0.05" sec"^(-1) . Calculate the rate constant of the reverse reaction.

The rate constant for a first order reaction is 60 s^(-1) . How much time will it take to reduce the initial concentration of the reactant to its (1^(th))/(16) values ?

Compound A reacts by first order kineties. At 25^(@)C , the rate constant of the reaction is 0.60 sec^(-1) . What is the half life of A ?

The rate constant of a first order reaction is 2.0xx10^(-6)s^(-1) . The initial concentration of the reactant is 0.10 "mol dm"^(-3) . What is the value of the initial rate ?