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The initial rate of a first order reacti...

The initial rate of a first order reaction is `5.2xx10^(-6) "mol lit"^(-1)s^(-1)` 298 K. When the initial concentration of reactant is `2.6xx10^(-3)"mol lit"^(-1)`, calculate the first order rate constant of the reaction at the same temperature.

Text Solution

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Given data : Rate `= 5.2xx10^(-6)"mol lit"^(-1)s^(-1)`
Initial concentration `[A]=2.6xx10^(-3)`
Formula : Rate `= k [A]^(1)`
Solution : Rate `= 5.2xx10^(-6)"mol lit"^(-1)sec^(-1)`
`= k xx 2.6xx10^(-3)lit^(-1)`
`=(5.2xx10^(-6)"mol lit"^(-1)sec^(-1))/(2.6xx10^(-3)"mol lit"^(-1))`
`therefore k = 2xx10^(-3)s^(-1)`
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