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NaHCO3 decomposes into: 2NaHCO(3(s)) h...

`NaHCO_3` decomposes into:
`2NaHCO_(3(s)) hArrNa_(2)CO_(3(s))+CO_(2(g))+H_(2)O_((g))`
The equilibrium pressure is 1.04 atm the `K_(p)` for the reaction is

A

`0.2704` `atm^(2)`

B

`2.704` `atm^(2)`

C

`27.04` `atm^(2)`

D

`270.4` `atm^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`P_(CO_(2)) + P_(H_(2)O) = P_(eqm)` which is `1.04 atm`
`K_(p)=P_(CO_(2)) * P_(H_(2)O)`
`P_(CO_(2)) = P_(H_(2)O)`
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