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For the reversible reaction 2H2S((g)) ...

For the reversible reaction
`2H_2S_((g)) hArr 2H_(2(g))+S_(2(g))`
The equilibrium concentrations, are
`[H_2S]=0.5` mole/litre
`[H_2]=0.4` mole/litre
`[S_2]=0.4` mole/litre
The value of 'K' would be

A

`0.004` mole/litre

B

`0.08` mole/litre

C

`0.016` mole/litre

D

`0.16` mole/litre

Text Solution

Verified by Experts

The correct Answer is:
C
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