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1/sqrtx (sqrtx+1/sqrtx)^2...

`1/sqrtx (sqrtx+1/sqrtx)^2`

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int(sqrtx+1/sqrtx)^2 dx=

y = sqrtx + 1/sqrtx

y= log(sqrtx+1/sqrtx)

y = x+sqrtx+1/sqrtx

(d)/(dx)(sqrtx+(1)/(sqrtx))^2=

(d)/(dx)(sqrtx+(1)/(sqrtx))^2=

int (1/sqrtx-sqrtx)dx

Integrate: (a) (3)/(2)sqrt3 (b) (3)/(2sqrtx) (c ) sqrtx+(1)/(sqrtx)

Integrate: (a) (3)/(2)sqrt3 (b) (3)/(2sqrtx) (c ) sqrtx+(1)/(sqrtx)