Let `A="{"-1,0,1")"a n df={(x , x^2): xA}dot` Show that `f: AvecA` is neither one-one nor onto.

Explanation

`f(x) = x^2`

`:. f(-1) = 1, f(0) = 0, f(1) = 1`

`=>f(-1) = f(1) = 1`

It means, `f(x)` is not one-one.

Now, range of `f = {0,1}`

`A = {-1,0,1}`

As, Range of `f != A`, `f` is not onto.

`:. f: A->A` is neither one-one nor onto.