cos(n+1)alpha*cos(n-1)alpha+sin(n+1)alpha*sin(n-1)alpha=

If a cos^(3)alpha+3a cos alpha sin^(2)alpha=ma sin^(3)alpha+3a cos^(2)alpha sin alpha=n, then (m+n)^((2)/(3))+(m-n)^((2)/(3))=

f_(n)(a)=(sin alpha+sin3 alpha+sin5 alpha+...+sin(2n-1)alpha)/(cos alpha+cos3 alpha+cos5 alpha+...+cos(2n-1)alpha) Then,the value of f_(4)((pi)/(32)) is equal to

If alpha-beta=(2n+1)(pi)/2, n epsilon Z then [(cos^(2) alpha, cos alpha sin alpha),(cos alpha sin alpha, sin^(2)alpha)][(cos^(2) beta, cos beta sin beta),(cos beta sin beta, sin^(2) beta)]=

If a cos^(3)alpha+3a cos alpha*sin alpha=m and a sin^(3)alpha+3a cos^(3)alpha sin^(3)alpha=n then (m+n)^((2)/(3))+(m-n)^((2)/(3))

If a cos^(3)alpha+3a cos alpha sin^(2)alpha=m and a sin^(2)alpha+3a cos^(2)alpha sin alpha=n then (m+n)^((2)/(3))+(m-n)^((2)/(3))=

If n=1,2,3,......, then cos alpha cos2 alpha cos4 alpha.........cos2^(n-1)alpha is equal to

If n=1,2,3,……. then cos alpha cos 2 alpha cos 4 alpha ……. Cos 2^(n-1) alpha is equal to