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12x^(2)+17x-5...

12x^(2)+17x-5

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I. 12x^(2) + 17x+ 6 = 0" " II. 6y^(2) + 5y + 1 = 0

solve 16x^(2)+17x+5

If first degree terms and constant term are to be removed from the equation 12x^(2)+7xy-12y^(2)-17x-31y-7=0 , then the origin must be shifted at shifted at the point .

If first degree terms and constant term are to be removed from the equation 12x^(2)+7xy-12y^(2)-17x-31y-7=0 , then the origin must be shifted at shifted at the point .

Transform 12x^(2)+7xy-12y^(2)-17x-31y-7=0 to rectangular through the point (1, -1) inclined at an angle tan^(-1)((4)/(3)) to the original axes.

Transform 12x^(2)+7xy-12y^(2)-17x-31y-7=0 to rectangular axes through the point (1, -1) inclined at an angle tan^(-1)((4)/(3)) to the original axes.

Transform 12x^(2)+7xy-12y^(2)-17x-31y-7=0 to rectangular axes through the point (1, -1) inclined at an angle tan^(-1)((4)/(3)) to the original axes.

Factories 6x^(2) + 17x + 12