x^(3)y^(4)=(x-7)^(7)*[[(PAGE)/(DATE)],[D]

x^(3)y^(4)=(x+y)^(7) ,find (dy)/(dx)

y = x ^ (3) y ^ (4) = (x + y) ^ (7)

x^(3)y^(4)=(x-y)^(7) Differentiate it and

2x^(2)x3xy^(2)x4x^(3)y^(5) is equal to: 24x^(6)y^(6)(b)24x^(6)y^(7)24x^(7)y^(6)(d)24x^(7)y^(7)

(dy)/(dx)=(3y-x+7)/(x-7y-3)

(4)/(x)+(3)/(y)=1,(8)/(x)-(9)/(y)=7

If x:y=7:3, then the value of (xy+y^(2))/(x^(2)-y^(2)) is (3)/(4) b.(4)/(3) c.(3)/(7) d.(7)/(3)

(4)/(x)+5y=7 and (3)/(x)+4y=5

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))