The expression `x-[y-{z-(bar(x-y)}-(x+y)+z]` when simplified reduces to

x-[y-{z-(x-bar(y-z)}]=

Factorize of the expression: a^3x+a^2(x-y)-a(y+z)-z\

Simplify x - [ y - { z - (2x - bar(y+z)) }]

Factorize of the expression: a^(3)x+a^(2)(x-y)-a(y+z)-z

Simplify : x - y - {x-y - (x+y)-bar(x-y)}

Simplify : (-x-y-z)^2-(x+y-z)^2 .

If (x+y) prop z when y is constant and (z+x) prop y when z is constant . Then prove that (x+y+z) prop yz , when when y and z are both constant.