A die is thrown three times, find the probability that 4 appears on the third toss if it is given that 6 and 5 appear respectively on first two tosses.

Explanation

Here,

`A = `Event that `6` and `5` appears on first two tosses.

It means third toss can have any of the six values.


`:. n(A) = 6`

Let `B = `Event that `4` appears on the third toss.


Now, `(AnnB) = {(6,5,4)}`

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