A pair of dice is thrown. Find the probability of getting 7 as the sum, if it is known that the second die always exhibits an odd number.

Explanation

When second is odd then there are only `18` possible outcomes,

`(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)`

`(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)`

`(1,5)(2,5)(3,5)(4,5)(5,5)(6,5)`

With the sums,


There are `3` outcomes that sum to `7`.

So,probabiility`=3/(18)=1/6`