Evaluate : `int_1^e(logx)/xdx`

Explanation

We have, `int_1^e​logxdx`

=`[logx∫1dx]_1^e​−int_1^e((d/dx)​logx∫1dx)dx`


=`[eloge−1log(1)]−int_1^e​1dx`

=`e−[x]_1^e​=e−[e−1]=1`