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(IE)(1) and (IE)(2) of Mg((g)) are 740, ...

`(IE)_(1)` and `(IE)_(2)` of `Mg_((g))` are `740, 1540 kJ mol^(-1)`. Calculate percentage of `Mg_((g))^(+)` and `Mg_((g))^(2+)` if 1g of `Mg_((g))` absorbs `50.0kJ` of energy.

A

`% Mg^(+) = 50` and `% Mg^(+2) = 50`

B

`% Mg^(+) = 70.13` and `%Mg^(+2) = 29.87`

C

`%Mg^(+) = 75` and `%Mg^(+2) = 25`

D

`%Mg^(+) = 60` and `%Mg^(+2) = 40`

Text Solution

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The correct Answer is:
B
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