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The formation of oxide ion O^(2-)(g) fro...

The formation of oxide ion `O^(2-)(g)` from oxygen atom requires first an exothermic and then an endothermic step as shown below
`O(g)+e^(-) rarr O^(-)(g), DeltaH^(-) = - 141 kj mol^(-1)`
`O^(-)(g) +e^(-) rarr O^(2-) (g), DeltaH^(-) =+ 780 kj mol^(-1)`
Thus, process of formation of `O^(2-)` in gas phase is unfavourable even through `O^(2-)` is isoelectronic with neon. It is due to the fact that

A

oxygen is more electronegative

B

addition of electron in oxygen results in larget size of the ion

C

electron repulsion outweights the stability gained by achieving noble gas configuration

D

`O^(-)` ion has comparatively smaller size than oxygen atom

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The formation of the oixde ion, O^(2+)(g) from oxygen atom requires first an exothermic and then an endothermic step as shown below: O(g)+e^(-) rarr O^(-)(g), Delta H^(O)=-141kJ mol^(-) O(g)+e^(-) rarr O^(-)(g), H^(O)=-kJ mol^(-) Thus the process of formation of O^(2-) in gas phase is neon. It is due to the fact that

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