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M+(X+Y)NH(3) rarr [M(NH(3))(x)]^(2+)+ 2[...

`M+(X+Y)NH_(3) rarr [M(NH_(3))_(x)]^(2+)+ 2[e^(-)(NH_(3))_(4)]^(-)` where M=alkaline earth metal. Value of x is …..

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The alkali metals dissolve in ammonia to give a deep blue solution which is conducting in nature. M+(x+y)NH_3rarr[M(NH_3)_x]^(2+)+2[e(NH_3)_y]^(-) Which of the following is not true about the solutions of alkli metals in liquid ammonia ?

If the solution 0.5 M NH_(3) and stability constant for A^(+)(NH_(3))_(2) is K_(stb)=([Ag(NH_(3))_(2)]^(+))/([Ag^(+)(aq)][NH_(3)]^(2))=6.4xx10^(7), then find the solubility of AgCl in the above solution K_(sp)of AgCl=2xx10^(-10)

The dissociation constant of [M (NH_(3))_(2)]^(+) complex into M^(+) and Ammonia is 1xx10^(-17) . The standard reduction poential of the same metal electrode [E_(M^(+),M)^(@)] is 1.02 V . Hence E^(@) of the half cell reaction : [M(NH_(3))_(2)]^(+)+e^(-)rarrM(s)+2NH_(3) is found to be chi xx 10^(-2) . Express the value of x to the nearest integer ? (Given R = 8.3 and 2.3 log x = log_(e )x )__

In the reaction [CoCI_(2)(NH_(3))_(4)]^(o+)rarr[CoCI_(3)(NH_(3))_(3)]+NH_(3) , only one isomer of the complex product is obtained Is the initial complex cis or trans ? .

Dilute solutions of alkali metals in liquid NH_(3) are blue. It is the ammoniated electron which is responsible for the blue colour of the solution, and the electrical conductivity is due to the ammoniated cation, [M(NH_(3))_(x)]^(+) as well as the ammoniated electrons, [e(NH_(3))_(y)]^(-) , values of x and y depend on the extent of solvation (by NH_(3) ). Dilute solutions are paramagnetic due to free electrons. What happens if alkali metals is allowed to react with concentrated liquid ammonia?

All alkali metals dissolve in anhydrous liquid ammonia to give blue colour solution. It is the ammoniated electron which is reponsible for the blue colour of the solution, and the electrical conductivity is due to the ammoniated cation, [M(NH_(3))_(x)]^(+) as well as the ammoniated electron, [e(NH_(3))_(y)]^(-) , value of x and y depend on the extent of solvation by NH_(3) . Dilute solutions are paramagnetic due to free ammoniated electrons. Q. Which of the following statement about solution of alkali metals in liquid ammonia is correct?