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S-I: Addition of HBr to HC-=C CH(2)CH=CH...

S-I: Addition of `HBr` to `HC-=C CH_(2)CH=CH_(2)` give `HC=CBrCH_(2)CH=CH_(2)`
S-II: A triple bond is more reactive than a double.

A

S-I&II are correct, S-II is correct explanaion of S-I

B

S-I&II are correct, S-II is not correct explanation of S-I

C

S-I is true, but S-II is false

D

S-I is false, but S-II is true.

Text Solution

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The correct Answer is:
A
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