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What is the range of a projectile thrown...

What is the range of a projectile thrown with velocity `98 m//s` with angle `30^(@)` from horizontal ?

A

`490sqrt(3)m`

B

`245sqrt(3)m`

C

`980sqrt(3)m`

D

100m

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The angle of which the velocity vector of a projectile thrown with a velocity u at an angle theta to the horizontal will take with the horizontal after time t of its being thrown up is

    A
    `theta`
    B
    `tan^(-1)((theta)/t)`
    C
    `tan^(-1)((v cos theta)/(vsin theta-"gt"))`
    D
    `tan^(-1)((vsin theta-"gt")/(v cos theta))`

  • A ball is projected with velocity 80 m//s and at an angle of 30^(@) from horizontal, the range will be -

    A
    562 m
    B
    286 m
    C
    188 m
    D
    1130 m

  • Figure shows a projectile thrown with speed u = 20 m/s at an angle 30^(@) with horizontal from the top of a building 40 m high. Then the horizontal range of projectile is

    A
    `20 sqrt(3)` m
    B
    `40 sqrt(3)` m
    C
    40 m
    D
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