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The height y and distance x along the ho...

The height `y` and distance `x` along the horizontal plane of a projectile on a certain planet are given by `x = 6t m` and `y = (8t^(2) - 5t^(2))m`. The velocity with which the projectile is projected is

A

`8 ms^(-1)`

B

`9 ms^(-1)`

C

`10 ms^(-1)`

D

`(10//3) ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`v_(y) = (dy)/(dt) = 8 - 10t, v_(x) = (dx)/(dt) = 6`
At `t = 0, v_(y) = 8 ms^(-1)` and `v_(x) = 6 ms^(-1)`
`:. V = sqrt(v_(x)^(2) +v_(y)^(2)) = 10 ms^(-1)`
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