The position of a particle moving in the xy plane at any time t is given by `x=(3t^2-6t)` metres, `y=(t^2-2t)` metres. Select the correct statement about the moving particle from the following

Options

A. The acceleration of the particle is zero at `t = 0s`
B. The velocity of the particle is zero at `t = 0s`
C. The velocity of the particle is zero at `t = 1s`
D. The velocity and acceleration of the particle are zero

Answer

C

Explanation

`v_(x) = (dx)/(Dt) = 6t =- 6, a_(x) = (dv_(x))/(dt) = 6 ms^(-2)`
`v_(y) = 2t -2, a_(Y) = (dv_(y))/(dt) = 2ms^(-2)`
At `t = 2s, v_(x)` and `v_(y)` both are zero. Hence, net velocity iszero.