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A particle's velocity changes from (2hat...

A particle's velocity changes from `(2hat I +3 hatj) ms^(-1)` in to `(3 hati - 2hatj) ms^(-1)` in 2s. Its average acceleration in `ms^(-2)` is

A

`-(hati + 5hatj)`

B

`(hati +5 hatj)//2`

C

zero

D

`(hati -5hatj)//2`

Text Solution

Verified by Experts

The correct Answer is:
D
`a_(av) = (Deltav)/(Delta t) = (3hati - 2hatj - 2hati - 3hatj)/(2) = (hati - 5hatj)/(2)`
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