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A particle is projected with a velocity ...

A particle is projected with a velocity of `20 ms^(-1)` at an angle of `60^(@)` to the horizontal. The particle hits the horizontal plane again during its journey. What will be the time of impact ?

A

`3.53 s`

B

`2.4s`

C

`1.7s`

D

1s

Text Solution

Verified by Experts

The correct Answer is:
A
The particle hits the horizontal plane again at time.
`T = (2u sin theta)/(g) = (40 xx sin 60^(@))/(9.8) = 3.53s`
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