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A particle is projected at an angle of `45^(@)` with a velocity of `9.8 ms^(-1)`. The horizontal range will be (Take, `g = 9.8 ms^(-2))`

A

`9.8m`

B

`4.9m`

C

`(9.8)/(sqrt(2))`

D

`9.8 sqrt(2)`

Text Solution

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The correct Answer is:
A
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DC PANDEY-MOTION-Check Point 4.2
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