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A projectile fired with initial velocity...

A projectile fired with initial velocity u at some angle `theta` has a range R . If the initial velocity be doubled at the same angle of projection, then the range will be

A

2R

B

`R//2`

C

R

D

4R

Text Solution

Verified by Experts

The correct Answer is:
D
`R = (u^(2) sin 2 theta)/(g)`
`:. R prop u^(2)`
If initial velocity be doubled at some angle of projection, then range will become four times.
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