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The horizontal range of a projectile is ...

The horizontal range of a projectile is `4 sqrt(3)` times its maximum height. Its angle of projection will be

A

`60^(@)`

B

`37^(@)`

C

`30^(@)`

D

`45^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
Given range, `R = 4sqrt(3)H`
`rArr (2u^(2) sin theta cos theta)/(g) = 4 sqrt(3) ((u^(2) sin^(2) theta)/(2g)) rArr tan theta = (1)/(sqrt(3))`
`:. theta = 30^(@)`
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DC PANDEY-MOTION-Check Point 4.2
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