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A bomber moving horizontally with 500m//...

A bomber moving horizontally with `500m//s` drops a bomb which strikes ground in 10s. The angle of strike with horizontal is

A

`tan^(-1) ((1)/(5))`

B

`60^(@)`

C

`45^(@)`

D

`tan^(-1)(5)`

Text Solution

Verified by Experts

The correct Answer is:
A
Horizontal component of velocity `v_(x) = 500 ms^(-1)` and vertical component of velocity while striking the ground can be given as
`v_(y) = 0 + 10 xx 10 = 100 ms^(-1)`
`:.` Angle with which it strikes the ground
`theta = tan^(-1) ((v_(y))/(y_(x))) = tan^(-1) ((100)/(500)) = tan^(-1)((1)/(5))`
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