Home
Class 11
PHYSICS
Assertion In projectile motion, if time ...

Assertion In projectile motion, if time of flight is 4s, then maximum height will be 20 m. (Take, `g = 10 ms^(-2))`
Reason Maximum height `= (gT)/(2)`.

A

If both Asseration and Reason are correct and Reason is the correct explanation of Assertion

B

If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion

C

If Assertion is true but Reason is false

D

If Assertion is false but Reason is true

Text Solution

Verified by Experts

The correct Answer is:
C
`H = (u^(2)sin^(2)theta)/(2g)` and `T = (2u sin theta)/(g)`
`:. u sin theta = (gT)/(2)`
`:.` Maximum height, `H = ((g^(2)T^(2)//4))/(2g) = (gT^(2))/(8) = (g(4)^(2))/(8) = 20m`
Promotional Banner

Topper's Solved these Questions

  • MOTION

    DC PANDEY|Exercise Match the Columns|4 Videos

  • MOTION

    DC PANDEY|Exercise C. Medical entrances gallery|1 Videos

  • MOTION

    DC PANDEY|Exercise B. Medical entrance|1 Videos

  • MEASUREMENT AND ERRORS

    DC PANDEY|Exercise Subjective|19 Videos

  • MOTION IN A PLANE

    DC PANDEY|Exercise (C )Medical entrances gallery|32 Videos

Similar Questions

Explore conceptually related problems

Assertion In projectile motion, if time of flight is made two times, then maximum height will become four times. Reason T prop sin theta and H prop sin^(2) theta , where theta is angle of projection.

In a projectile motion, velocity at maximum height is

Motion In A Plane |Projectile Motion|Time Of Flight|Range|Maximum Height

A stone is projected in air. Its time of flight is 3s and range is 150m. Maximum height reached by the stone is (Take, g = 10 ms^(-2))

Introduction || Time OF flight, Range, Maximum Height

Range of a projectile with time of flight 10 s and maximum height 100 m is : (g= -10 m//s ^2)

Projectile motion|| Time OF flight|| Max height|| Range

" For a projectile the ratio of the square of the time of flight to its maximum height is "

For a projectile if the time of flight is T , the maximum height is H and the horizontal range is R . Find the (a) the maximum height in terms of T and (b) the maximum horizontal range in terms of R and H .

Assertion : If time of flight in a projectile motion is made two times, its maximum height will become four times. Reason : In projectile motion H prop T^2 , where H is maximum height and T the time of flight.