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Assertion At height 20 m from ground , v...

Assertion At height 20 m from ground , velocity of a projectile is `v = (20 hati + 10 hatj) ms^(-1)`. Here, `hati` is horizontal and `hatj` is vertical. Then, the particle is at the same height after 4s.
Reason Maximum height of particle from ground is 40m (take, `g = 10 ms^(-2))`

A

If both Asseration and Reason are correct and Reason is the correct explanation of Assertion

B

If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion

C

If Assertion is true but Reason is false

D

If Assertion is false but Reason is true

Text Solution

Verified by Experts

The correct Answer is:
B
`t = (2u_(y))/(g) = (2xx 20)/(10) = 4s`
`H = 20 +(u_(y)^(2))/(2g) = 20 +((20)^(2))/(2 xx 10) = 40m`
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