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A body is projected horizontally from th...

A body is projected horizontally from the top of a tower with a velocity of `10 m//s`.If it hits the ground at an angle `45^(@)`, th vertical component of velocity when it hits ground in `m//s` is

A

`10 sqrt(2)`

B

`5sqrt(2)`

C

5

D

10

Text Solution

Verified by Experts

The correct Answer is:
D
The horizontal component of velocities
`v_(x) = u = 10 ms^(-1)`

Now, `tan theta = tan 45^(@) = (v_(y))/(v_(x)) = (v_(y))/(10) rArr v_(y) = 10 ms^(-1)`
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