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Find the magnitude of the centripetal ac...

Find the magnitude of the centripetal acceleration of a particle on the tip of a blade, ` 0 .30 ` metre in diameter, rotating at `1200` revolution per minute.

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Given, Diameter =`0.30m`
`therfore" Radius",r=(0.30)/(2)=0.15m`
and Frequency, `n=1200"rev min"^(-1)`
`=(1200)/(60)=20rps`
`therefore"Angular velocity",omega=2pin=2pixx20=40pi" rad s"^(-1)`
Therefore, centripetal acceleration, `a_(c)=omega^(2)r`
`rArr" "a_(c)=0.15xx(40pi)^(2)rArra_(c)=2366.3ms^(-2)`
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