A particle moves in a circular path of radius `0.5 m` at a speed that uniformly increases. Find the angular acceleration of particle if its speed changes from `2.0m//s` to `4.0 m//s` in `4.0s`

Explanation

The tangential acceleration of the particle is
`a_(t)=(dv)/(dt)=(4-2)/(4)=0.5ms^(-2)`
The angular acceleration is `alpha=(a_(t))/(r)=(0.5)/(0.5)-1"rad s"^(-2)`