A car is travelling along a circular curve that has a radius of `50m` . If its speed is `16m//s` and is increasing uniformly at `8m//s^(2)` . Determine the magnitude of its acceleration at this instant.

Explanation

Given, tangential acceleration `a_(t)=8ms^(-2)`
Radius R = 50 m, Speed v = 16`ms^(-1)`
`therefore"Radial acceleration" a_(r)=(v^(2))/(R)=((16)^(2))/(50)=(256)/(50)`
Magnitude of net acceleration of the car.
`a=sqrt(a_(t)^(2)+a_(r)^(2))=sqrt((8)^(2)+((256)/(50))^(2))=9.5ms^(-2)`