A train has to negotiate a curve of radius 2000 m. By how much should the outer rail be raised with respect to inner rail for a speed of `72"km h^(-1)`. The distance between the rails is 1 m.

Explanation

Given, `v=72"km h"^(-1)=72xx(5)/(18)=20ms^(-1)`
l = 1 m, r = 2000 m, `g=10ms^(-2)`
We have, `tan theta=(v^(2))/(rg)`

Also, `tantheta=(h)/(l)`
`rArr" "(v^(2))/(rg)=(h)/(l)`
`rArr" "h=(v^(2)l)/(rg)`
`therefore" h=((20)^(2)xx1)/(2000xx10)=(1)/(50)m`
`=(100)/(50)=2cm`