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One end of a string of length 1 m is tie...

One end of a string of length 1 m is tied to a body of mass `0.5` kg. It is whirled in a vertical circle with angular velocity 4 rad `s^(-1)`. Find the tension in the string when the body is at the lower most point of its motion. (take, g = 10 `ms^(-1)`)

Text Solution

AI Generated Solution

To find the tension in the string when the body is at the lowest point of its circular motion, we can follow these steps: ### Step 1: Identify the forces acting on the body At the lowest point of the circular motion, two forces act on the body: 1. The gravitational force (weight) acting downward, \( F_g = mg \) 2. The tension in the string, \( T \), acting upward ### Step 2: Calculate the gravitational force ...
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Knowledge Check

  • One end of a string of length 1.0 m is tied to a body of mass 0.5 kg . It is whirled in a vertical circle with angular frequency 4 rads^(-1) .The tension in the string when the body is at the lower most points of its motion will be equal to (Take ,g =10ms^(-2))

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    13N
  • A body of mass 0.4 kg is whirled in a vertical circle making 2 rev/sec. If the radius of the circle is 1.2 m, then tension in the string when the body is at the top of the circle, is

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    41.56N
    B
    89.86N
    C
    109.86
    D
    115.86N
  • A body of mass 0.4 kg is whirled in a vertical circle making 2 rev/sec . If the radius of the circle is 2 m , then tension in the string when the body is at the top of the circle, is

    A
    `41.56 N`
    B
    `89.86 N`
    C
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    D
    `122.2 N`
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