A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is

Options

A. `(2piv)/(T)`
B. `(2pir)/(T)`
C. `(2pir^(2))/(T)`
D. `(2piv^(2))/(T)`

Answer

A

Explanation

Acceleration `=omega^(2)r=(v^(2))/(r)=omegav=(2pi)/(T)v`