A paticle of mass `m` is executing uniform circular motion on a path of radius `r`. If `p` is the magnitude of its linear momentum, then the radial force acting on the particle is

Options

A. pmr
B. `(rm)/(p)`
C. `(mp^(2))/(r)`
D. `(p^(2))/(rm)`

Answer

D

Explanation

Radial force `=(mv^(2))/(r)=(m)/(r)((p)/(m))^(2)=(p^(2))/(mr)`