A motercyclist wants to drive on the vertical surface of wooden 'well' of radius 5 m, with a minimum speed of `5sqrt5ms^(-1)`. The minimum value of coefficient of friction between the tyres and the well must be (take, g = 10`ms^(-2)`)

Options

A. `0.10`
B. `0.20`
C. `0.30`
D. `0.40`

Answer

D

Explanation

`N=(mv^(2))/(R),mg=muN=(mumv^(2))/(R)`
`therefore` Coefficient of friction between the tyres and wall of the well will be
`mu=(Rg)/(v^(2))=(5xx10)/((5sqrt5)^(2))=0.40`