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A particle is moving in a vertical circl...

A particle is moving in a vertical circle with constant speed. The tensions in the string when passing through two positions at angles `30^@` and `60^@` from vertical (lowest position) are `T_1` and `T_2` respectively. Then

A

`T_(1)=T_(2)`

B

`T_(2)gtT_(1)`

C

`T_(1)gtT_(2)`

D

Data insufficient

Text Solution

Verified by Experts

The correct Answer is:
C

Tension, `T=(mv^(2))/(r)+mg costheta`
For `theta=30^(@)`
`T_(1)=(mv_(1)^(2))/(r)+"mg cos 30"^(@)`
For `theta=60^(@),T_(2)=(mv_(2)^(2))/(r)+"mg cos 60"^(@)`
`therefore" "T_(1)gtT_(2)" as "v_(1)gtv_(2)` and `cos30^(@)gtcos60^(@)`
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