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A particle of mass m is moving in a plan...

A particle of mass `m` is moving in a plane along a circular path of radius `r`. Its angular momentum about the axis of rotation is `L`. The centripetal force acting on the particle is.

A

`(L^(2))/(mr)`

B

`(L^(2))/(mr^(2))`

C

`(L^(2))/(mr^(3))`

D

`(L)/(mr^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C

`L=mvr thereforev=(L)/(mr)`
`F=(mv^(2))/(r)=(L^(2))/(mr^(3))`
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