A moter-cyclist moving with a velocity of 144 `kmh^(-1)` on a flat road takes a turn on the road at a point where the radius of curvature of the road is 40 m. The acceleration due to gravity is 10 `ms^(-2)`. In order to avoid sliding, he must bend with respect to the vertical plane by an angle

Options

A. `theta=tan^(-1)(4)`
B. `theta=45^(@)`
C. `theta=tan^(-1)(2)`
D. `theta=tan^(-1)(6)`

Answer

A

Explanation

`v=144kmh^(-1)=144xx(5)/(18)ms^(-1)=40ms^(-1)`
`tantheta=(v^(2))/(Rg)`
`rArr" "tantheta=((40)^(2))/(40xx10)=(1600)/(400)=4`