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A circular disc of radius R is rotating ...

A circular disc of radius R is rotating about its axis O with a uniform angular velocity `omega"rad s"^(-1)` as shown in the figure. The magnitude of the relative velocity of point A relative to point B on the disc is

A

zero

B

`Romegasin((theta)/(2))`

C

`2Romegasin((theta)/(2))`

D

`sqrt3Romegasin((theta)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
C

`|v_(AB)|=|v_(A)-v_(B)|=sqrt((Romega)^(2)+(Romega)^(2)-2(Romega)(Romega)costheta)`
`=2Romegasin.(theta)/(2)`
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