Three particles A, B and C move in a circle of radius `r=(1)/(pi)`m, in anti-clockwise direaction with speed `1ms^(-1), 2.5ms^(-1)` and `2ms^(-1)` respectively. The initial position of A, B and C are as shown in figure.

The ratio of distance travelled by B and C by the instant A, B and C meet for the first time is

Options

A. `3:2`
B. `5:4`
C. `3:5`
D. `3:7`

Answer

B

Explanation

`(d_(B))/(d_(C))=(v_(B^(t)))/(v_(C^(t)))=(v_(B))/(c_(C))=(2.5)/(2)=(5)/(4)`