Two particles A and B start at the origin O and travel in opposite directions along the circular path at constant speeds `v_(A)=1.4ms^(-1)` and `v_(B)=3ms^(-1)` respectively. The time when they collide and the magnitude of the acceleration of B just before this happens are

Options

A. `14.35,0.45ms^(-2)`
B. `1.25,0.2ms^(-2)`
C. `11.25,0.5ms^(-2)`
D. `14.55,0.3ms^(-2)`

Answer

A

Explanation

`3t+1.4t=2piR=20pi`
`therefore" "t=(10pi)/(2.2)=14.3srArra=(v_(B)^(2))/(R)=0.45ms^(-2)`