Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is `v_(0)`, then the ratio of tensions in the three sections of the string is `(T_(BC):T_(AB):T_(DA))`

Options

A. `3:5:7`
B. `3:4:5`
C. `7:11:6`
D. `3:5:6`

Answer

D

Explanation

Let `omega` is the angular speed of revolution.

`T_(3)=momega^(3)(3l)`
`T_(2)-T_(3)=momega^(2)2lrArrT_(2)=momega^(2)(5l)`
`T_(1)-T_(2)=momega^(2)lrArrT_(1)=momega^(2)(6l)`
`T_(3):T_(2):T_(1)=3:5:6`