The ratio of angular speed of a second-had to the hour-hand of a watch is

Options

A. `3600:1`
B. `720:1`
C. `72:1`
D. `60:1`

Answer

B

Explanation

We know that, angular speed of a watch
`omega=(theta)/(t)rArromega prop (1)/(t)`
Hence, `(omega_("second"))/(omega_("hour"))=(t_("hour"))/(t_("second"))=(12xx3600)/(60)=720`
i.e. `(omega_("second"))/(omega_("hour"))=(720)/(1)`