If the length of second's hand of a clock is 10 cm, the speed of its dip (in `cm s^(-1)`) is nearly

Options

A. 2
B. `0.5`
C. `1.5`
D. 1

Answer

C

Explanation

We know that, `(because r=10cm)`
`omega=(pi)/(30)"rads"^(-1)`
`therefore" "v = r omega=10xx(pi)/(30)=(pi)/(3)"rads"^(-1)`
`=(3.14)/(3)"rad s"^(-1)=1.046~=1"cm s"^(-1)`