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The law goverening electrostatics is cou...

The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that
`ointbar(E).bar(ds)=(q)/(epsilon_(0))`
where `ds` is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface.
The `SI` unit of electric flux is

A

weber

B

`"newton coulomb"^(-1)`

C

Volt `xx` metre

D

`"joule coulomb"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
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The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that ointbar(E).bar(ds)=(q)/(epsilon_(0)) where ds is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface. Consider a uniform electric field E=3xx10^(3)hat(i)NC^(-1) what is the flux thorugh a square of side 10 cm whose plane is parallel to the y-z plane?

The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that ointbar(E).bar(ds)=(q)/(epsilon_(0)) where ds is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface. Gauss throrem in electrostatics states that electric flux oint(E.ds)=(q)/(epsilon_(0)) where S is the Gaussian surface ,the electric field E is due to all the charges

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Knowledge Check

  • The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that ointbar(E).bar(ds)=(q)/(epsilon_(0)) where ds is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface. Consider a uniform electric field E=3xx10^(3)hat(i)NC^(-1) what is the flux thorugh a square of side 10 cm whose plane is parallel to the y-z plane?

    A
    `30NC^(-1)m^(2)`
    B
    `20NC^(-1)m^(2)`
    C
    `10NC^(-1)m^(2)`
    D
    zero

  • The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that ointbar(E).bar(ds)=(q)/(epsilon_(0)) where ds is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface. Gauss throrem in electrostatics states that electric flux oint(E.ds)=(q)/(epsilon_(0)) where S is the Gaussian surface ,the electric field E is due to all the charges

    A
    both inside and outside the surface `S`
    B
    outside the surface `S`
    C
    inside the surface
    D
    on the surface `S`

  • Gauss's law can help in easy calculation of electric field due to

    A
    Moving charge only
    B
    Any charge configuration
    C
    Any, symmetrical charge configuration
    D
    Some special symmetric charge configuration
    • DC PANDEY-ELECTROSTATICS-Check point 1.5
    1. The law goverening electrostatics is coulomb's law.In priciple coulomb...

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    2. A surface element vec(ds) = 5 hat(i) is placed in an electric field v...

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    3. A cube of side a is placed in a uniform electric field E = E(0) hat(i)...

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    4. Flux coming out from a positive unit charge placed in air, is

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    5. If the electric flux entering and leaving an enclosed surface respecti...

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    6. Charge of 2 C is placed at the centre of a cube. What is the electric ...

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    7. For a given surface the Gauss's law is stated asoint vecE.dvecA=0. Fro...

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    8. The total electric flux emanating from a closed surface enclosing an a...

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    9. The inward and outward electric flux for a closed surface in unit of N...

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    10. If the flux of the electric field through a closed surface is zero , ...

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    11. Consider the charge configuration and a spherical Gaussian surface as ...

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    12. q(1),q(2),q(3) and q(4) are point charges located at point as shown in...

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    13. The Gaussian surface for calculating the electric field due to a charg...

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    14. If Coulomb's law involved 1/r^3 instead of 1/r^2, would Gauss's law st...

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    15. Two parallel infinite line charges with linear charge densities +lambd...

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    16. An infinite line charge produces a field of 9xx10^(4) NC at a distance...

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    17. A charge of 17.7 xx 10^(-4)C is distributed uniformly over a large she...

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    18. From what distance should a 100 eV electron be fired towards a large m...

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    19. If the field near the earth's surface is 300V m^(-1) directed downward...

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    20. A thin spherical shell of metal has a radius of 0.25 m and carries a c...

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