Home
Class 12
PHYSICS
Assertion : If a dipole is enclosed by a...

Assertion : If a dipole is enclosed by a surface, then according to Gauss's law, electric flux linked with it will be zero.
Reason : The charge enclosed by a surface is zero.

A

If both Assertion and Reason are correct and Reason is the correct explanation of Assertion

B

If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion

C

If Assertion is true but Reason is false

D

If Assertion is false but Reason is true

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    DC PANDEY|Exercise Match the columns|5 Videos

  • ELECTROSTATICS

    DC PANDEY|Exercise Medical entrances gallery|37 Videos

  • ELECTROSTATICS

    DC PANDEY|Exercise Taking it together|105 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITORS

    DC PANDEY|Exercise (C) Chapter exercises|50 Videos

  • GRAVITATION

    DC PANDEY|Exercise All Questions|120 Videos

Similar Questions

Explore conceptually related problems

What is Gauss's law for electric flux ?

What is the electric flux linked with closed surface?

Electric Flux and Gauss Law

Assertion: No net charge can exist in the region where electric field is uniform. Reason: For any type of Gaussian surface selected within the region of a uniform electric field, the angle between electric field intensity and area normal is 90^@ everywhere. Hence, electric flux linked with the selected Gaussian surface is equal to zero. If the net electric flux is zero for some Gaussian surface then according to Gauss's law the net charge enclosed within the surface must be zero.

Which of the following statement is correct ? If E = 0 , at all points of a closed surface. a. the electirc flux through the surface is zero. b. the total charge enclosed by the surface is zero.

Assertion(A):If Gaussian surface does not enclose any charge then vec(E) at any point on the Gaussian surface must be zero. Assertion(R ):No net charge is enclosed by Gaussians surface,so net flux passing through the surface is zero.

A charge q is enclosed as shown, below the electric flux is