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A parallel plate capacitor (C=50 muF, d=...

A parallel plate capacitor `(C=50 muF, d=4mm)` is charged to `200V` and then charging battery is removed. Now a dielectric slab `(K=4)` of thickness `2mm` is placed between the plates. Find new potential difference across capacitor.

A

62.5 V

B

12.5 V

C

10 V

D

15 V

Text Solution

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The correct Answer is:
A
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