Find the equivalent capacitance between `A` and `B`.`A`: area of each plate, `d`: separation between the plates.

Find out equivalent capacitance between A and B. (take each plate Area = A)

Find out equivalent capacitance between A and B. (take each plate Area = A)

The equivalent capacitance between A and B is neo A/d. Take plate area as A and separation between the plates as d. Find n. A. .B

Find out equivalent capacitance between A and B. (take each plate Area = A and distance between two conjugative plates is d)

Four metal plates are arranged as shown in the figure. Capacitance between X and Y (Ararr" Area of each plate, d"rarr "distance between the plates") is

(a) Find the potential difference between the plates of a parallel plate capacitor of capacitance 5muF if a charge +800muC is placed on one plate and- 200muC on another plate. (b) The charege given to plate are as shown. The capacitance between the adjacent plates is C . find the charge on outer surface of plate 3 , and potential difference between plate 1 and 2 . (c) If A is area of each plate and d is separation between adjacent plates, find the charge supplied by battery. (d) Five idential capacitor plates each of area A are arranged such that adjacent plates are at a distance d apart. the plates are connected to a source of emf V as shown. what is the magnitude and nature of charge on plates 1 and 3 respectively?

The diagram shows an arrangement of identical metal plates placed parallel to each other and the variation of potential between the paltes by dotted lilne. Using the details given in diagram, the equivalent capacitance connected across the plate No. 2 and plate No. 4 is (Separation between the consecutive plates =L , area of each plate =A )

Find the charge on each plate given area of each plate is A and separation between two consecutive plates is d.

Find the equivalent capacitance between point a and b in the following arrangement of the plates .